Day 19 — Linear & quadratic functions
Day 19 — Linear & quadratic functions
Stage II · concept day
Goal: Master slope-intercept and point-slope forms; use parallel/perpendicular slope conditions; analyze quadratics via vertex form, discriminant, and completing the square; read graph features.
Why this matters
Linear models are first-order approximations everywhere. Quadratics appear in free-fall idealization, parabolic trajectories, and optimization of \(ax^2+bx+c\). Completing the square unlocks vertex and the quadratic formula.
Theory
Slope of a line
Through points \((x_1,y_1)\), \((x_2,y_2)\) with \(x_1\neq x_2\): \[m=\frac{y_2-y_1}{x_2-x_1}.\]
- \(m>0\) rising; \(m<0\) falling; \(m=0\) horizontal.
- Vertical lines: \(x=\) constant; slope undefined (not a function \(y=f(x)\)).
Forms of a line
- Slope-intercept: \(y=mx+b\) (\(b\) = \(y\)-intercept).
- Point-slope: \(y-y_1=m(x-x_1)\).
- Standard: \(Ax+By=C\).
- Two-point: use slope then point-slope.
Parallel and perpendicular
- Parallel lines: same slope \(m_1=m_2\) (and distinct intercepts if distinct lines).
- Perpendicular lines (in plane with standard metric): \(m_1 m_2=-1\) if both slopes defined.
(Horizontal \(\perp\) vertical.)
Proof sketch of perp condition. Direction vectors \((1,m_1)\), \((1,m_2)\) have dot product \(1+m_1 m_2=0\). \(\square\)
Quadratic functions
\[f(x)=ax^2+bx+c,\qquad a\neq 0.\]
- Parabola graph; opens up if \(a>0\), down if \(a<0\).
- Axis of symmetry: \(x=-\dfrac{b}{2a}\).
- Vertex: \(\biggl(-\dfrac{b}{2a},\; f\biggl(-\dfrac{b}{2a}\biggr)\biggr)\).
- \(y\)-intercept \(c\); \(x\)-intercepts = roots if real.
Completing the square
\[ \begin{align*} ax^2+bx+c&=a\biggl(x^2+\frac{b}{a}x\biggr)+c\\ &=a\biggl(x+\frac{b}{2a}\biggr)^2 - a\biggl(\frac{b}{2a}\biggr)^2 +c\\ &=a\biggl(x+\frac{b}{2a}\biggr)^2 + \biggl(c-\frac{b^2}{4a}\biggr). \end{align*} \]
Vertex form: \(f(x)=a(x-h)^2+k\) with vertex \((h,k)\).
Discriminant and quadratic formula
From completing the square (or formula derivation): \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a},\qquad \Delta=b^2-4ac.\]
| \(\Delta\) | Roots |
|---|---|
| \(>0\) | two distinct real |
| \(=0\) | one real (double) |
| \(<0\) | no real roots (two complex) |
Graph features checklist
Vertex, axis, intercepts, direction, max/min value \(k\) if vertex form.
Linear vs quadratic growth (preview)
Tables: linear has constant first differences; quadratic has constant second differences.
Derivation of the quadratic formula
Start from \(ax^2+bx+c=0\) with \(a\neq 0\): \[ x^2+\frac{b}{a}x=-\frac{c}{a}. \] Add \(\bigl(\frac{b}{2a}\bigr)^2\) to both sides: \[ \biggl(x+\frac{b}{2a}\biggr)^2=\frac{b^2}{4a^2}-\frac{c}{a}=\frac{b^2-4ac}{4a^2}. \] If \(\Delta=b^2-4ac\ge 0\), \[ x+\frac{b}{2a}=\pm\frac{\sqrt{\Delta}}{2a},\qquad x=\frac{-b\pm\sqrt{\Delta}}{2a}. \] If \(\Delta<0\), no real \(x\). This is the formula—not a separate magic spell.
Sum and product of roots
If roots \(r,s\) (real or complex), \(r+s=-\frac{b}{a}\) and \(rs=\frac{c}{a}\) for monic-normalized \(ax^2+bx+c\).
Proof. \(a(x-r)(x-s)=a(x^2-(r+s)x+rs)=ax^2+bx+c\). \(\square\)
Axis of symmetry \(x=\frac{r+s}{2}=-\frac{b}{2a}\) when roots real.
Section formula / midpoint
Midpoint of \((x_1,y_1)\) and \((x_2,y_2)\) is \(\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)\).
The axis \(x=-\frac{b}{2a}\) is the midpoint of the two real roots on the \(x\)-axis.
Worked examples
Example 1 — Slope
Through \((1,2)\) and \((4,8)\): \(m=\frac{6}{3}=2\). Equation \(y-2=2(x-1)\) i.e. \(y=2x\).
Example 2 — Parallel / perp
Line through \((0,1)\) parallel to \(y=3x-2\): \(y=3x+1\).
Perpendicular: slope \(-\frac{1}{3}\), \(y-1=-\frac{1}{3}(x-0)\).
Example 3 — Intercept form to graph
\(2x+3y=6\): \(x\)-intercept \(3\), \(y\)-intercept \(2\).
Example 4 — Vertex formula
\(f(x)=2x^2-8x+3\). \(h=\frac{8}{4}=2\), \(f(2)=8-16+3=-5\). Vertex \((2,-5)\).
Example 5 — Complete the square
\(x^2+6x+5=(x+3)^2-9+5=(x+3)^2-4\). Vertex \((-3,-4)\).
Example 6 — With \(a\neq 1\)
\(2x^2+8x+1=2(x^2+4x)+1=2(x+2)^2-8+1=2(x+2)^2-7\).
Example 7 — Discriminant
\(x^2-4x+4=0\): \(\Delta=0\), root \(x=2\).
\(x^2+x+1=0\): \(\Delta=1-4=-3<0\), no real roots.
Example 8 — Quadratic formula
\(2x^2-3x-2=0\): \(\Delta=9+16=25\), \(x=\frac{3\pm 5}{4}\). \(x=2\) or \(x=-\frac{1}{2}\).
Example 9 — Factored graph
\(f(x)=(x-1)(x-4)=x^2-5x+4\). Roots \(1,4\); vertex at \(x=2.5\), \(f(2.5)=-2.25\).
Example 10 — Max problem
Rectangular enclosure three sides fence \(L=20\), side \(x\), depth \(y\), \(2x+y=20\), area \(A=x(20-2x)=20x-2x^2\). Vertex \(x=5\), \(A=50\).
Example 11 — Linear table
\(x=1,2,3,4\); \(y=3,5,7,9\): first differences \(2,2,2\) → linear slope \(2\).
Example 12 — Quadratic table
\(y=1,4,9,16\): first diff \(3,5,7\); second \(2,2\) → quadratic.
Example 13 — Perp check
Slopes \(2\) and \(-\frac{1}{2}\): product \(-1\). ✓
Example 14 — From vertex
Vertex \((1,-2)\), passes through \((3,6)\), \(a>0\): \(y=a(x-1)^2-2\). \(6=a\cdot 4-2\Rightarrow 4a=8\), \(a=2\). \(y=2(x-1)^2-2\).
Example 15 — Full quadratic formula derivation numeric
\(2x^2-4x-6=0\). Divide by 2: \(x^2-2x-3=0\). \((x-1)^2=4\), \(x-1=\pm 2\), \(x=3\) or \(x=-1\). Formula: \(\Delta=16+48=64\), \(x=\frac{4\pm 8}{4}\).
Example 16 — Sum/product of roots
\(x^2-5x+6=0\): roots \(2,3\); sum \(5=-(-5)\); product \(6\). Useful check after solving.
Example 17 — No real intersection line-parabola
\(y=x^2\) and \(y=-x-1\): \(x^2+x+1=0\), \(\Delta=-3<0\)—no real intersection.
Example 18 — Horizontal and vertical
Through \((3,-2)\): horizontal \(y=-2\) (slope \(0\)); vertical \(x=3\) (undefined slope, not \(y=f(x)\)).
Example 19 — Second differences proof sketch
\(f(n)=an^2+bn+c\). First difference \(\Delta f(n)=f(n+1)-f(n)=a(2n+1)+b\). Second \(\Delta^2 f(n)=\Delta f(n+1)-\Delta f(n)=2a\). Constant \(2a\).
Example 20 — Optimizing a quadratic profit
\(P(x)=-x^2+12x-20\) (toy). Vertex at \(x=6\), \(P(6)=16\). Domain if \(x\) is quantity in \([0,12]\): max at vertex inside interval.
Exercises
Easy
- Slope through \((0,0)\) and \((5,10)\).
- Equation: slope \(-3\), \(y\)-intercept \(4\).
- Vertex of \(y=x^2-4x+1\) using \(-b/(2a)\).
- Discriminant of \(x^2+2x+5\).
- Parallel to \(y=-x+1\) through \((2,3)\).
Medium
- Point-slope then slope-intercept: through \((-1,4)\) and \((3,2)\).
- Perpendicular to \(y=\frac{2}{3}x-1\) through \((0,0)\).
- Complete the square: \(x^2-5x+6\); find vertex form.
- Complete the square: \(3x^2-12x+5\).
- Solve \(x^2-2x-15=0\) by formula and by factoring.
- Find max/min of \(f(x)=-2x^2+8x-1\).
- \(x\)-intercepts of \(f(x)=x^2-3x-10\).
- Write equation of vertical and horizontal lines through \((2,-5)\).
Hard / proof
- Derive the quadratic formula by completing the square for \(ax^2+bx+c=0\).
- Prove that vertex \(x\)-coordinate is \(-b/(2a)\) using axis of symmetry or calculus-free: average of roots when \(\Delta\ge 0\), or complete square.
- Prove: lines with slopes \(m\) and \(-\frac{1}{m}\) (\(m\neq 0\)) are perpendicular via direction vectors.
- Show constant second differences for \(f(n)=an^2+bn+c\) on integers \(n\).
- For \(f(x)=ax^2+bx+c\) with \(a>0\), prove \(f(x)\ge f\bigl(-\frac{b}{2a}\bigr)\) for all \(x\).
- Find all lines through \((1,2)\) with slope \(\pm 1\); equations.
- Relate \(\Delta\) to factoring over reals.
Challenge / CS-flavored
- Linear interpolation between points \((x_0,y_0)\), \((x_1,y_1)\): write \(y\) as function of \(x\).
- Complexity: \(T(n)=an+b\) vs \(S(n)=cn^2\)—for large \(n\), which dominates? (qualitative)
- Screen coordinates: line from pixel \((0,0)\) to \((w,h)\); slope.
- Projectile height \(h(t)=-5t^2+20t+2\): max height and time.
- Fit: uniquely determine \(y=mx+b\) from two distinct points—why unique?
Intercept form of a line
If \(x\)-intercept \(a\neq 0\) and \(y\)-intercept \(b\neq 0\): \(\frac{x}{a}+\frac{y}{b}=1\).
Distance from point to line (formula stated)
For line \(Ax+By+C=0\) and point \((x_0,y_0)\): \[\mathrm{dist}=\frac{|Ax_0+By_0+C|}{\sqrt{A^{2}+B^{2}}}.\] Useful for geometry checks; derive later via projection if desired.
Discriminant and factoring link
\(\Delta\) perfect square in \(\mathbb{Q}\) helps rational roots; over \(\mathbb{R}\), \(\Delta\ge 0\) suffices for real factorization into linears.
Vertex as optimization
For \(a>0\), vertex is global minimizer; \(a<0\) maximizer. Business “profit quadratic” word problems use this.
Extra exercises
- Derive slope-intercept form from two points algebraically.
- Complete the square for \(5x^{2}-20x+6\).
- Find \(k\) so \(x^{2}+kx+9\) is a perfect square trinomial.
- Equation of line parallel to \(3x-y=2\) with \(y\)-intercept \(-4\).
- Show the axis of symmetry is midway between real roots when \(\Delta>0\).
CS connection
Linear regression is fitting lines; quadratic forms appear in optimization objectives. Bresenham-style line drawing uses slopes. Discriminant decides existence of real intersection. Vertex form is “change of coordinates” to center a feature.
Common pitfalls
| Pitfall | What to do instead |
|---|---|
| Slope \(\frac{x_2-x_1}{y_2-y_1}\) | Rise over run: \(\Delta y/\Delta x\) |
| Forgetting \(a\) when completing square | Factor \(a\) out of \(x\) terms first |
| \(\Delta\) formula wrong | \(b^2-4ac\) |
| Parallel vs equal lines | Same slope, check intercepts |
| \(m_1 m_2=1\) for perp | Product \(-1\) |
| Vertical line as \(y=mx+b\) | Cannot; \(x=\) const |
Fully worked extra examples
E15 — Complete the square with \(a\neq 1\) fully.
\(3x^{2}-12x+7=3(x^{2}-4x)+7=3(x^{2}-4x+4-4)+7=3((x-2)^{2}-4)+7=3(x-2)^{2}-12+7=3(x-2)^{2}-5\).
Vertex \((2,-5)\); opens up; min \(-5\).
E16 — Quadratic formula numeric.
\(x^{2}-x-1=0\): \(\Delta=5\), \(x=\frac{1\pm\sqrt{5}}{2}\). Golden ratio \(\varphi=\frac{1+\sqrt{5}}{2}\).
E17 — Parallel through a point.
Line \(2x-3y=6\) has slope \(\frac{2}{3}\) (rewrite \(y=\frac{2}{3}x-2\)). Through \((3,1)\): \(y-1=\frac{2}{3}(x-3)\).
E18 — Intercept form.
Intercepts \(4\) and \(-2\): \(\frac{x}{4}+\frac{y}{-2}=1\Rightarrow \frac{x}{4}-\frac{y}{2}=1\). Multiply by \(4\): \(x-2y=4\).
End-of-day synthesis problems
S1. Line through \((2,-1)\) and \((-4,5)\): slope, point-slope, slope-intercept.
S2. Line through \((0,3)\) perpendicular to \(y=\frac{1}{2}x-1\).
S3. Complete the square: \(f(x)=2x^{2}-12x+5\); vertex and min value.
S4. Derive quadratic formula from \(ax^{2}+bx+c=0\) by completing the square (full writeup).
S5. Discriminant cases for \(x^{2}+kx+1=0\) as \(k\) varies.
S6. Graph features of \(f(x)=-(x-2)^{2}+3\): vertex, direction, intercepts.
S7. Fence problem: three sides, total \(30\) m, maximize area; optimal dimensions.
S8. Show second differences of \(n^{2}\) equal \(2\) for consecutive integers \(n\).
Deep dive — Geometry of \(ax^2+bx+c\)
Completing the square is a translation of the graph: \(y-k=a(x-h)^2\) shifts the basic parabola \(y=ax^2\) so the vertex sits at \((h,k)\). Stretch \(|a|\) and reflect if \(a<0\). Linear functions are degenerate “parabolas with \(a=0\)”—constant first differences, infinite “vertex” nowhere. Parallel lines never meet; perpendicular slopes multiply to \(-1\) because direction vectors are orthogonal under the dot product.
Synthesis
Lines: slope, intercepts, parallel/perp. Quadratics: complete the square → vertex form; discriminant → number of real roots; formula is completed square solved for \(x\). Optimization of \(ax^2+bx+c\) on \(\mathbb{R}\) is reading the vertex. Tables: first differences linear, second quadratic.
S9. Derive \(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\) for \(a=3\), \(b=-6\), \(c=0\) both by factoring and by formula.
S10. Line through \((1,1)\) perpendicular to \(2x+y=4\); slope-intercept form.
S11. For \(f(x)=x^2-6x+5\), give vertex, roots, and \(y\)-intercept without a calculator.
S12. Prove: if \(\Delta>0\), axis of symmetry is midpoint of the two roots.
Checkpoint
- Write line equations from slope/points
- Use parallel and perpendicular conditions
- Convert quadratic to vertex form by completing the square
- Use discriminant and quadratic formula
- Identify vertex, intercepts, max/min
- S4 proof-level derivation once
Write two takeaways in your own words.
Quick reference card
| Topic | Formula |
|---|---|
| Slope | \(m=\frac{y_2-y_1}{x_2-x_1}\) |
| Line | \(y=mx+b\) or \(y-y_1=m(x-x_1)\) |
| Parallel | \(m_1=m_2\) |
| Perpendicular | \(m_1 m_2=-1\) |
| Vertex \(x\) | \(-b/(2a)\) |
| Vertex form | \(a(x-h)^{2}+k\) |
| Discriminant | \(\Delta=b^{2}-4ac\) |
| Quadratic formula | \(\frac{-b\pm\sqrt{\Delta}}{2a}\) |
Tomorrow
Day 20 — Exponential growth. \(a^x\) growth; half-life/doubling; linear vs exp tables; compound interest; logs as inverse of exp.